解方程2x²-4x+1=0(用配方法解)

解:2x-4x+1=0x-2x+1/2=0x-2x+1-1+1/2=0x-2x+1=1-1/2(x-1)=1/2x-1=±√(1/2)x=1±(√2)/2∴x1=1+(√2)/2,x2=1-(√2)/2亲,请您采纳,您的采纳是我的动力,谢谢.

2x-4x+1 = 02(x-2x+1) - 1=02(x-1) - 1 = 0(x-1) = 1/2x-1 = ± (√2)/2x = 1± (√2)/2如果本题有什么不明白可以追问,如果满意请点击“选为满意答案”

解:2x+4x-1=0 x+2x-1/2=0 (x+1)-3/2=0 x+1=±√6/2 x1=-1+√6/2,x2=-1-√6/2

解:2x-4x+1 = 2(x-2x+1) - 1 = 2(x-1) - 1 = 0∴(x-1) = 1/2∴x-1 = ± (√2)/2∴x = 1± (√2)/2

x 1 =1+ ,x 2 =1- . 试题分析:先把常数bai项-1移到方程du右边,再把二次项系数化为1,最后方程两边都加上一次项系数-2的一半的zhi平方,进行配方即可求出方程的解dao.试题解析:∵2x 2 -4x-1=0∴回2x 2 -4x=1∴x 2 -2x= x 2 -2x+1= 即:(x-1) 2 = 解得:x 1 =1+ ,x 2 =1- .考点: 解一元二答次方程-----配方法.

1,用公式法解方程 x-2x-1=0 x=[2±√(-2)+4]/2 =1±√2 即x1=1+√2,x2=1-√22,配方法:3x-4x-2=0 x-4/3x-2/3=0 (x-2/3)-4/9-2/3=0 x-2/3=±1/3√10 x1=(2+√10)/3,x2=(2-√10)/33,x+3x-10=0 (x+5)(x-2)=0 x1=-5,x2=24,-3x-x+2=0 3x+x-2=0 (x+1)(3x-2)=0 x1=-1,x2=2/35,x-4x=0 x(x-4)=0 x1=0,x2=4

2x^2-4x+1=0x^2-2x+1/2=0x^2-2x= -1/2x^2-2x+1=1-1/2(x-1)^2=1/2x-1= ±√(1/2)= ±√2/2x1=1+√2/2 x2=1-√2/2

2x-4x-1=0x^2-2x=1/2x^2-2x+1=1+1/2(x-1)^2=3/2x-1=±2分之根号6x1=1+2分之根号6, x2=1-2分之根号6

2x-4x+1=0 2(x-2x+1)-1=0 (x-1)^2=1/2 x-1=√2/2 或x-1=√2/2 解得x1=√2/2 +1,x2=-√2/2 +1 2x-4x+1=0 2(x-2x+1)-1=0 (x-1)=1/2 x-1=√2/2 或x-1=√2/2 解得x1=√2/2 +1,x2=-√2/2 +1

2(X^2+2x+1)-2+1=0 2(x+1)^2-1=0 (x+1)^2=1/2 x=√2/2-1 x2=-1-√2/2